How ?
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twistor59 wrote:A thread based on a silly crackpot article that I posted in pseudoscience has, through an appalling lack of discipline, degenerated into a discussion of actual science. So, for that reason, I feel bound to move the discussion to here....
The issue is the following: we all know that light propagates in a vacuum at speed c, and "consists" of these mysterious entities called photons. The question is - how does light propagate in a medium ? We know that the speed is lower in the medium, this is because we're dealing with c = 1/sqrt(με) instead of c = 1/sqrt(μ0ε0), but this is just a statement of the classical behaviour. Is there any way to understand this in terms of the fundamental interactions between the photon and the atoms in the medium ?
The propagation can't result from photons being absorbed by atoms and re-emitted, since this would place restrictions on the frequencies involved. (This is discussed here).
Certainly, the medium is more polarizable than the vacuum - it has charge distributions from the electron orbitals which can be polarized by the field of the photon. Maybe that's all that needs to be said, even in the quantum case.
There is some discussion of the QED analysis of propagation in a medium here.
zaybu wrote:twistor59 wrote:A thread based on a silly crackpot article that I posted in pseudoscience has, through an appalling lack of discipline, degenerated into a discussion of actual science. So, for that reason, I feel bound to move the discussion to here....
The issue is the following: we all know that light propagates in a vacuum at speed c, and "consists" of these mysterious entities called photons. The question is - how does light propagate in a medium ? We know that the speed is lower in the medium, this is because we're dealing with c = 1/sqrt(με) instead of c = 1/sqrt(μ0ε0), but this is just a statement of the classical behaviour. Is there any way to understand this in terms of the fundamental interactions between the photon and the atoms in the medium ?
The propagation can't result from photons being absorbed by atoms and re-emitted, since this would place restrictions on the frequencies involved. (This is discussed here).
Certainly, the medium is more polarizable than the vacuum - it has charge distributions from the electron orbitals which can be polarized by the field of the photon. Maybe that's all that needs to be said, even in the quantum case.
There is some discussion of the QED analysis of propagation in a medium here.
I don't know about the first article. The author makes assertions with no evidence supporting his claim. So I have ignored
it.
In the second article, the propagation of photons is understood to be c. What is discussed is the on-shell energy versus off-shell energy in the photon-atom scattering process. The whole idea that the speed of photon would change is not addressed simply because it is a given that it is c, ( c=1, in the paper). The hint is given in this sentence: "However, all operators commute with each other at space-like separation in quantum field theory, which makes such superluminal amplitude never violate the causality [1, 15]." (page 4). That is also repeated in the conclusion.
The propagating behavior of photons in optical media is interesting due to a refracted photon has same energy but different momentum to it has in vacuum. In quantum field theory[1], the two words on-shell and off-shell differentiate whether a particle’s momentum and energy obeying or disobeying the relativistic energy-momentum relation (mass shell). For an on-shell particle, its momentum and energy obeys the relativistic relation H0 = √P2 c2 + m2 c4 . For an off-shell particle, its momentum and energy disobey the relativistic relation, which means H0 ≠√P2 c2 + m2c4. When a photon is propagating in vacuum, it is on-shell due to it obeys the relation hω0 = ℏk0 c. When a photon is propagating in an optical medium, its frequency is same to it has in vacuum, however, its wave vector is changed by the refraction. The Abraham-Minkowski controversy [2–6] is a century-old problem which debates that the momentum of a photon in the optical media is k0 /n (Abraham momentum) or n k0 (Minkowski momentum), where n is the refraction index of the optical media. No matter which momentum is right, the refracted photon seems to be always off-shell in optical media due to hω0 /c ≠n k0and hω0 /c ≠k0 /n


The_Metatron wrote:Doesn't this have to do with the finite but small amount of time the atoms in the medium take to absorb then re-emit the photons?

twistor59 wrote:
But the first paragraph of the Zhang paper states:The propagating behavior of photons in optical media is interesting due to a refracted photon has same energy but different momentum to it has in vacuum. In quantum field theory[1], the two words on-shell and off-shell differentiate whether a particle’s momentum and energy obeying or disobeying the relativistic energy-momentum relation (mass shell). For an on-shell particle, its momentum and energy obeys the relativistic relation H0 = √P2 c2 + m2 c4 . For an off-shell particle, its momentum and energy disobey the relativistic relation, which means H0 ≠√P2 c2 + m2c4. When a photon is propagating in vacuum, it is on-shell due to it obeys the relation hω0 = ℏk0 c. When a photon is propagating in an optical medium, its frequency is same to it has in vacuum, however, its wave vector is changed by the refraction. The Abraham-Minkowski controversy [2–6] is a century-old problem which debates that the momentum of a photon in the optical media is k0 /n (Abraham momentum) or n k0 (Minkowski momentum), where n is the refraction index of the optical media. No matter which momentum is right, the refracted photon seems to be always off-shell in optical media due to hω0 /c ≠n k0and hω0 /c ≠k0 /n
so the speed of the photon that's propagating through the medium is not c. Propagation in a medium seems to force it to be off shell.
zaybu wrote:twistor59 wrote:
But the first paragraph of the Zhang paper states:The propagating behavior of photons in optical media is interesting due to a refracted photon has same energy but different momentum to it has in vacuum. In quantum field theory[1], the two words on-shell and off-shell differentiate whether a particle’s momentum and energy obeying or disobeying the relativistic energy-momentum relation (mass shell). For an on-shell particle, its momentum and energy obeys the relativistic relation H0 = √P2 c2 + m2 c4 . For an off-shell particle, its momentum and energy disobey the relativistic relation, which means H0 ≠√P2 c2 + m2c4. When a photon is propagating in vacuum, it is on-shell due to it obeys the relation hω0 = ℏk0 c. When a photon is propagating in an optical medium, its frequency is same to it has in vacuum, however, its wave vector is changed by the refraction. The Abraham-Minkowski controversy [2–6] is a century-old problem which debates that the momentum of a photon in the optical media is k0 /n (Abraham momentum) or n k0 (Minkowski momentum), where n is the refraction index of the optical media. No matter which momentum is right, the refracted photon seems to be always off-shell in optical media due to hω0 /c ≠n k0and hω0 /c ≠k0 /n
so the speed of the photon that's propagating through the medium is not c. Propagation in a medium seems to force it to be off shell.
Off-shell means that E2 ≠ p2c2 + m2c4.
zaybu wrote:
It's an indication that you are dealing with inelastic scattering and has nothing to do with the speed of the photon varying. The article goes on how this inelastic scattering is tied in with bound states and off-shell amplitudes in Feynman propagators. In one instance, it considers: "In the U-channel, the bound electron emits a photon at x1 and absorbs a photon at x2 with x2 > x1." That is in fact, we are looking at photons being absorbed and emitted (See fig. 2), which is what I have said in the other thread.

No, I don't think they do that. If they did, they'd be emitting a photon whose frequency is determined by the energy difference in the electron levels.

cavarka9 wrote:Nice
No, I don't think they do that. If they did, they'd be emitting a photon whose frequency is determined by the energy difference in the electron levels.
Which brings me to the question, how much amount of energy is absorbed by transparent objects. Must not be much(atleast in visible range) if it has to be transparent right?.
I will now always look at glass with admiration.
Then the whole optical properties of materials, refractive index of elements are infact due to perturbative contributions?.

MrsC wrote:
There's nothing as good as combustible products.

twistor59 wrote:Yes, very little visible light is absorbed - I vaguely remember that infrared gets absorbed more (?) Unfortunately I never studied condensed matter physics, so I don't have much knowledge of these mechanisms.

itwistor59 wrote:
So, the scattering they're talking about here is the sum of all the perturbative contributions to the photon's propagation. These are virtual processes - they don't actually happen. If a photon were really absorbed, it would raise the energy level of an atom. We're just adding up their contributions to the final amplitude. When they're summed, the result is that the real transmitted photon propagates, in the medium, with a speed not equal to c.
We use the S-matrix formalism of bound-state QED to study the photon-atom scattering and give the off-shell propagating behavior of photons in atoms during the scattering. By considering the spontaneous emission of excited states
of bound electrons, we find that only the bound electrons in ground states are suitable to be the initial and final state ofS-matrix. Typical light-atoms scattering processes including Rayleigh scattering, Compton scattering, Raman scattering,
as well as the cycle of absorbing and emitting photons by atoms are all corresponding to certain Feynman diagrams in
the perturbation theory of bound-state QED. The inner bound electron lines in such Feynman diagrams are described by the
Feynman propagators,which can give the off-shell amplitudes of photons in atoms phenomenally.
zaybu wrote:itwistor59 wrote:
So, the scattering they're talking about here is the sum of all the perturbative contributions to the photon's propagation. These are virtual processes - they don't actually happen. If a photon were really absorbed, it would raise the energy level of an atom. We're just adding up their contributions to the final amplitude. When they're summed, the result is that the real transmitted photon propagates, in the medium, with a speed not equal to c.
That the speed of light in a material is not c is a classical result. But it's not because the photons have slowed down, but as the paper indicates, it can be explained using QED on emission and absorption, and the paper indicates how this is to be done:We use the S-matrix formalism of bound-state QED to study the photon-atom scattering and give the off-shell propagating behavior of photons in atoms during the scattering. By considering the spontaneous emission of excited states
of bound electrons, we find that only the bound electrons in ground states are suitable to be the initial and final state ofS-matrix. Typical light-atoms scattering processes including Rayleigh scattering, Compton scattering, Raman scattering,
as well as the cycle of absorbing and emitting photons by atoms are all corresponding to certain Feynman diagrams in
the perturbation theory of bound-state QED. The inner bound electron lines in such Feynman diagrams are described by the
Feynman propagators,which can give the off-shell amplitudes of photons in atoms phenomenally.
"off-shell amplitudes of photons" is not about velocity but related to calculating probabilities.
No where in the paper is there any implication that the speed of light has been changed. If it does, I'd like to know which equation says that.

twistor59 wrote:
You could then, in principle, compute a modified propagator - an amplitude for propagation through glass. In this propagator, the photon would have a mass. It would be off-shell.
You could then, in principle, compute a modified propagator - an amplitude for propagation through glass. In this propagator, the photon would have a mass. It would be off-shell.

twistor59 wrote:
But, if you read the paragraph carefully:You could then, in principle, compute a modified propagator - an amplitude for propagation through glass. In this propagator, the photon would have a mass. It would be off-shell.
twistor59 wrote:
small in magnitude for opaque media
large in magnitude for transparent media
have a phase behaviour which is the same as you'd get by giving the photon a mass whilst it was in the medium

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