Posted: Feb 19, 2012 8:38 am
by Darkchilde
This post will be about solving the third example:

[math]


Again we use the exact same methodology to differentiate the above example. Let's see it all term by term, and start differentiating:

[math]


So, for the first term we have: a=8, n=-3 and n-1=-3-1=-4; then the derivative for this term is:

[math]

[math]


Proceeding to the second term:

[math]


Here we have: a=-9, n=7 and n-1=7-1=6. Then this derivative will be:

[math]

[math]


The third term is a constant, -4, and so its derivative is equal to 0. So, the first derivative of our function will be equal to:

[math]


We also want to find the second derivative; again we follow the same method, as before.

[math]


We have a=-24, n=-4 and n-1=-4-1=-5; so the second derivative of the above will be:

[math]

[math]


And continuing with the second term of the first derivative:

[math]


Here we have a=-63, n=6 and n-1=6-1=5. Plugging in the numbers we get:

[math]

[math]


Putting the two terms together, we get the second derivative of our function:

[math]


Always remember to check the signs of each function; as I said earlier, a change of sign will give a vastly different result. I will do the last example later this afternoon.