Posted:

**Feb 27, 2011 3:20 pm**CdesignProponentsist's answer seems to be in conflict with your answer. Is it too forward to ask you two to fight it out?

It makes sense, but isn't the redshift only dependent on the gradient of the potential? For instance, in the case of 2 equal mass bodies, one smaller than its Schwarzschild radius, the other larger. Would then the redshift be different for both objects, while they have the same total potential?

I may want to get into the math's of this stuff...At some point.

I watched one simulation a while ago, but I see there's a lot more available nowadays.

p.s. I always thought of gravity as being nothing other than the curvature of spacetime (due to the presence of mass). Gravity being just our interpretation of the curvature, not an effect of it.

twistor59 wrote:Xaihe wrote:Since gravity is stronger at the surface of a planet than at the center of a planet, does that also mean spacetime is curved less at the center of the planet, or just that the gravitational effect is canceled? In the same effect, does time go slower or faster at the center of the earth than at the earth's surface? If spacetime is curved less due to this cancellation, what does this tell us about the goings on inside black holes?

Imagine you're in space and you watch a clock drifting towards the earth. You would see it ticking slower and slower as it approached the earth. If it carried onwards, sinking into the earth, then it would continue to tick slower and slower until it reached the centre. One way to think of it is that effectively it's sinking deeper and deeper into the potential well, and photons would have to work harder and harder to climb out of it, hence get more redshifted. The ticks of the clock are equivalent to the cycles of the photons.

The strength of the gravity is more related to the gradient of this potential, whereas for comparing clocks we want to compare the values of the potential at two separate points. So the local strength of the gravitational force is not relevant.

It makes sense, but isn't the redshift only dependent on the gradient of the potential? For instance, in the case of 2 equal mass bodies, one smaller than its Schwarzschild radius, the other larger. Would then the redshift be different for both objects, while they have the same total potential?

To do this quantitatively, you'd have to look at the Schwarzschild Interior solution and look at the behaviour of g00

I may want to get into the math's of this stuff...At some point.

Xaihe wrote:

In the same spirit, what happens to the shape and position of the event horizons of two black holes as they approach each other? I'd imagine an extending of the event horizons outward and a decrease of the event horizon between the two masses.

My own understanding of GR is too limited to figure this out, nor could I find the answer elsewhere. I suspect I'm employing some kind of naive view of spacetime curvature here.

If you google something like "merging black holes" you should find loads of computer simulations and animations of this.

I watched one simulation a while ago, but I see there's a lot more available nowadays.

p.s. I always thought of gravity as being nothing other than the curvature of spacetime (due to the presence of mass). Gravity being just our interpretation of the curvature, not an effect of it.